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2x^2-24x=-5x^2-2x-3
We move all terms to the left:
2x^2-24x-(-5x^2-2x-3)=0
We get rid of parentheses
2x^2+5x^2+2x-24x+3=0
We add all the numbers together, and all the variables
7x^2-22x+3=0
a = 7; b = -22; c = +3;
Δ = b2-4ac
Δ = -222-4·7·3
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-20}{2*7}=\frac{2}{14} =1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+20}{2*7}=\frac{42}{14} =3 $
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